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4.9t^2-17t-40=0
a = 4.9; b = -17; c = -40;
Δ = b2-4ac
Δ = -172-4·4.9·(-40)
Δ = 1073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{1073}}{2*4.9}=\frac{17-\sqrt{1073}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{1073}}{2*4.9}=\frac{17+\sqrt{1073}}{9.8} $
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